#2C_2H_2(l) + 5O_2(g) -> 4CO_2(g) + 2H_2O(g)# If the acetylene tank contains 37.0 mol of #C_2H_2# and the oxygen tank contains 81.0 mol of #O_2#, what is the limiting reactant for this reaction?
Is not dioxygen the limiting reagent....?
We might repropose the combustion reaction as...
…(I use the half-integral coefficients, because I find the arithmetic EASIER this way). And so each equiv acetylene requires
Your conditions propose a
You only gots
Note that welders can generally adjust the oxygen supply to their acetylene torches, and get reducing or oxidizing flames...