2log x-log 5 =-2?

1 Answer
May 21, 2018

#x=sqrt5/10#

Explanation:

As #2logx-log5=-2#

#2logx=-2log10+log5#

or #logx^2=log(5/10^2)#

or #x^2=5/10^2#

or #x=sqrt5/10#

Observe that though there could have been an answer #x=-sqrt5/10# too, but this does not in domain and hence has been omitted.