4.65 L of nitrogen at standard pressure is compressed into a 0.480 L container. What is the new pressure in mm Hg?

1 Answer
May 7, 2018

P_2P2 = 7362.5 mmHg

Explanation:

Boyle's Law
P_1P1V_1V1 = P_2P2V_2V2

Standard Temperature and Pressure in mmHg:
760 mmHg
https://www.thoughtco.com/stp-in-chemistry-607533
https://en.wikipedia.org/wiki/Standard_conditions_for_temperature_and_pressure

(760mmHg)(4.65L) = P_2P2(0.480L)

Divide (760mmHg * 4.65L) by (0.480L) to isolate for P_2P2.

(760 * 4.65)/(0.480) = 7604.650.480=P_2#

Simplify.

(3534/0.480)(35340.480) = P_2P2

7362.5 mmHg = P_2P2