# Question #40e4a

Mar 6, 2014

Start by converting the 234 g of fluorine to moles.

234g / 38 g = 6.15 moles ${F}_{2}$ (38 g is the molar mass of ${F}_{2}$)

No take the moles of ${F}_{2}$ and convert them to moles of HF by using the mole ratio from the balanced chemical equation.

6.15 moles ${F}_{2}$ x 2 moles $H F$ / 1 mole ${F}_{2}$ = 12.30 moles $H F$

Now use Avogadro's value 22.4 L/mole at STP to convert moles to liters.

12.30 moles $H F$ x 22.4 L / 1 mole = 275.52 L $H F$