# Question 0f321

Mar 11, 2014

The water absorbs 7360 J.

The formula is

q = mcΔT

where $q$ is the heat, $m$ is the mass, $c$ is the specific heat capacity, and ΔT is the temperature change.

$m = \text{32.0 g}$

$c = {\text{4.184 J·K"^-1"g}}^{-} 1$

ΔT = T_2 –T_1 = "(80.0 – 25.0) K" = "55.0 K"

q = mcΔT = 32.0 cancel("g") × "4.184 J"·cancel("K⁻¹g⁻¹") × 55.0 cancel("K") = "7360 J"#