# Question #fe2cf

Jul 2, 2015

The equation of motion in this case is:
$s = v t + 10$

#### Explanation:

If I got it correctly you have the following:

The equation of motion should be $s = v t$ where $s$ is the distance and $v$ is the velocity (no acceleration involved); but here you have to consider the initial position not at zero but at $10 m$ (when you start your stopwatch the car is at the $10 m$ mark!)) so you get:
$\textcolor{red}{s = v t + 10}$

At $t = 0$ your car is already at $s \left(0\right) = 10 m$ while at $t = 8 s$ your car is at $s \left(8\right) = v t + 10 = 5 \cdot 8 + 10 = 50 m$.

Hope it is not confusing!