$5400 is invested, part of it at 11% and part of it at 9%. For a certain year, the total yield is is 546.00. How much was invested at each rate?

1 Answer
Mar 24, 2018

Answer:

#$2400# invested at #9%#
#$3000# invested at #11%#

Explanation:

We can divide #$5400# by letting #5400-x# be the part invested at #11%# and the other #x# is invested at #9%#. We have the equation
#0.11(5400-x)+0.09x=546#. Solving for #x#. We have
#594-0.11x+0.09x=546#
#48=0.02x x = 2400#
Therefore we have
#$2400# invested at #9%#
#$3000# invested at #11%#