Question

Question #64b3c

Answer 1

Let us first find the function values at `t=1` and `t=2`.

`s(2)=-16(2)^2+16(2)+32=0`

`s(1)=-16(1)^2+16(1)+32=32`

The average rate of change of `s` on `[1,2]` can be found by

`{s(2)-s(1)}/{2-1}={0-32}/{1}=-32`

This means that the value of `s` decreases by `32` units on the average as `t` increases `1` unit.

I hope that this was helpful.