Question

Question #32af4

Answer 1

The answer is `132.5 g/(mol)`.

This is a pretty straighforward application of the ideal gas law, `PV = nRT`. In order to determine the gas' molar mass, we must first determine the number of moles for this particular set of paramaters:

`n_(gas) = (PV)/(RT) = ((743/760) * 109 * 10^(-3))/(0.082 * 358.15) = 0.004` moles

Notice how pressure was converted to atmospheres, volume to liters and temperature to K.

Therefore, the gas' molar mass is equal to

`molarmass = m_(gas)/n_(gas) = (0.530 g)/(0.004 mo l e s) = 132.5 g/(mol)`