Question

Question #273c3

Answer 1

molecular wt. of `Ba(OH)_2`=171g
no. of moles of `Ba(OH)_2`=2.3/171 =0.0134

1 mole of `Ba(OH)_2` dissociates to give 2x`N_a` number of `(OH)^-` ions
0.0134 moles gives =(0.0134x2x`N_a`)
here `N_a` =6.023 x `10^23`
= 0.161 x `10^23` `(OH)^-` ions