I'm a little confused by this...
Let's assume that an initial mass of
#O_2#was not in excess;
- The mass of
#O_2#was not supplimented when the mass of #Mg#was.
So, my best answer is DEPENDS ON THE
0.2g of Mg has reacted.
If the mass of Mg has increased by 0.335g then this must be equal to the mass of MgO.
So 1 mole weighs 40g
So no. moles MgO =
So no. moles Mg = 0.00835 since 1 mole MgO contains 1 mole Mg.
So mass Mg