# Question #a0b94

Dec 18, 2014

There is one valence electron in an atom of gold.

The electron configuration is :

$\left[X e\right] 4 {f}^{14} 5 {d}^{10} 6 {s}^{1}$

Where $\left[X e\right]$ is the configuration of xenon.

The electron in the highest energy level is a 6s electron. This is the valence electron.

Gold forms the Au(I) state though this is unstable and disproportionates to Au(III) and Au(0):

$3 A {u}^{+} \rightarrow A {u}^{3 +} + 2 A u$