Question

Question #091ee

Answer 1

The pH of your solution will be equal to 13.0.

Sodium hydroxide is a strong base, which means that it dissociates completely in aqueous solution to produce sodium cations, `Na^(+)`. and hydroxide anions, `OH^(-)`, according to the following chemical equation

`NaOH_((aq)) -> Na_((aq))^(+) + OH_((aq))^(-)`

Notice that 1 mole of sodium hydroxide produces 1 mole of `Na^(+)` and 1 mole of `OH^(-)` ions. This means that the concentration of the hydroxide ions will be equal to

`[OH^(-)] = [NaOH] = "0.1 M"`

You can use this concentration to determine the pOH of the solution

`pOH = -log([OH^(-)])`

`pOH = -log(0.1) = 1.0`

Therefore, the pH of the solution will be equal to

`pH_"sol" = 14 - pOH = 14 -1.0 = color(green)(13.0)`