# Question #1b3e3

##### 1 Answer
Jan 26, 2015

In order to calculate the mass of $\text{18.2 mL}$ of silver you must know its density, which is listed at ${\text{10.49 g/cm}}^{3}$.

$\text{18.2 mL" * ("1.0 cm"^3)/("1.0 mL") * ("10.49 g")/("1 cm"^3) = "190.9 g" = "191 g}$

So, what you basically have to do is implement the

$m = \rho \cdot V$

formula using conversion factors. Notice that the density is given in ${\text{g/cm}}^{3}$, which is equal to $\text{g/mL}$, like the second term suggests. The answer is rounded to three sig figs because that is the number of sig figs $\text{18.2}$ has.