# Question #1e0d7

$F = m \cdot a$
$F = m \cdot \frac{d}{\mathrm{dt}} \left(v\right)$
$F = m \cdot \frac{{d}^{2} L}{\mathrm{dt}} ^ 2$
Now we know differentiating adds a unit corresponding to the independent variable. Hence $F = {M}^{1} {L}^{1} {T}^{-} 2$