Question #9237e

Aug 11, 2016

The BCF (bioconcentration factor) is $60256$. Then let us calculate the rest.

Explanation:

According to Connell, D. W. (Bioaccumulation of Xenobiotic Compounds, 1990 CRC Press), BCF of DDT is $60256$ (or ${10}^{4.78}$).

So the DDT concentration in plankton is

$\text{BCF" * "concentration in water" = 60256 * 0.2 = "12051 mg/kg}$

Now we can calculate the concentration of DDT in fish (eating plankton). This is

$10 \cdot 12051 = \text{120510 mg/kg"" ""or" " 121 g/kg}$.

In the end, the concentration of DDT in a bird will be $\text{1210 g/kg}$. This cannot pass 1000 g per kg. It is highly recommended to check site-specific conditions (such as water hardness, pH, dissolved or suspended solids, etc.). And this concentration (computed one) cannot be observed in reality. I only assumed that a ten-fold increase in DDT in food chain occur. Maybe it is less than ten-fold.