Question

Question #53027

Answer 1

You will need 10.10 g of Al.

Step 1. Write the balanced chemical equation.

Word equation: iron(III) oxide + aluminum → aluminium oxide + iron

Unbalanced equation: Fe₂O₃ + Al → Al₂O₃ + Fe

Balanced equation: Fe₂O₃ + 2Al → Al₂O₃ + 2Fe

Step 2. Calculate the moles of Fe₂O₃

`"29.9 g Fe"_2"O"_3 × ("1 mol Fe"_2"O"_3)/("159.69 g Fe"_2"O"_3) = "0.1872 mol Fe"_2"O"_3"`

Step 3. Calculate the moles of Al

`"0.1872 mol Fe"_2"O"_3 × "2 mol Al"/("1 mol Fe"_2"O"_3) = "0.3745 mol Al"`

Step 4. Calculate the mass of Al

`"0.3745 mol Al" × "26.98 g Al"/"1 mol Al" = "10.10 g Al"`