Question #c44c2

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Answer 1 · 2015-04-05T16:49:41

$w = "-2 kJ"$

Start with the definitions.

$H = U + PV$ , so

$ΔH = ΔU + Δ(PV)$

If the pressure is constant,

$ΔH = ΔU + PΔV$

But $w = -PΔV$ , so

$ΔH = ΔU – w$

$w = ΔU – ΔH = "-2045 kJ – (-2043 kJ)" = "-2 kJ"$