You'd need 30 L of oxygen gas under those conditions of temperature and pressure to react with that much aluminium.
Start with the balanced chemical equation
Notice that you have a
So, you know the mass of aluminium that reacts, which means that you can determine the number of moles that react by using aluminium's molar mass
Use the mole ratio to determine how many moles of oxygen you need
All you have to do now is use the ideal gas law equation to solve for the volume you need
SIDE NOTE Do not forget to convert degrees Celsius and mmHg to Kelvin and atm, respectively.
Rounded to one sig fig, the number of sig figs given for the temperature, the answer will be