# Question #cee00

Apr 29, 2015

${M}_{M} = 116$

From $P V = n R T$, you get $n = \frac{P V}{R T}$

$n = \frac{37.6 \cdot 0.45}{8.314 \cdot 353} = \text{0.00576 moles}$

Then from $n = \frac{\text{grams}}{M} _ M$, you get

${M}_{M} = \text{grams"/"n}$

${M}_{M} = \text{0.668 g"/"0.0576 moles" = "115.97 g/mol}$