Question

Question #cee00

Answer 1

`M_M = 116`

From `PV = nRT`, you get `n= (PV)/(RT)`

`n= (37.6 * 0.45)/(8.314 * 353) = "0.00576 moles"`

Then from `n = "grams"/M_M`, you get

`M_M = "grams"/"n"`

`M_M = "0.668 g"/"0.0576 moles" = "115.97 g/mol"`