# Question #15e3f

x=4, $\frac{7 - \sqrt{129}}{2}$
First solve 24+2-${x}^{2}$= 5x-4,that is ${x}^{2}$ +3x-28=0 , or(x+7)(x-4)=0, giving x= -7, 4.
Next solve $24 + 2 x - {x}^{2}$= -5x+4, that is ${x}^{2} - 7 x - 20 = 0$, giving x=$\frac{7 + \sqrt{129}}{2}$, $\frac{7 - \sqrt{129}}{2}$.
Out of these four values, it can be verified that only x=4, $\frac{7 - \sqrt{129}}{2}$ satisfy the given equation.