Question #19ef4

2 Answers
May 20, 2015

Answer:

#"4.2 g"#

Explanation:

You have #"4.2 g"# of ethane in that much hexane solution.

Percent concentration by mass is defined as the mass of solute, in your case ethane, divided by the total mass of the solution, and multiplied by #100%#.

In order to be able to calculate the amount of ethane present in that much #"13.9% m/m""# hexane solution, you need to first figure out what the actual weight of the solution is.

To do that, use its density and volume

#rho = m/V => m = rho * V#

#m_"solution" = 0.611"g"/cancel("mL") * 50cancel("mL") = "30.55 g"#

You know that the mass of the solute accounts for #"13.9%"# of the solution, which means that

#"13.9%" = m_"ethane"/m_"solution" * 100% => m_"ethane" = ("13.9%" * m_"solution")/(100%)#

#m_"ethane" = (13.9cancel(%) * 30.55)/(100cancel(%)) = "4.246 g"#

Now, I'm going to give the answer rounded to two sig figs, even though you only gave one sig fig for the volume of the solution

#m_"ethane" = color(green)("4.2 g")#

May 20, 2015

4.2g

#M_("eth")/M_("soln")xx100=13.9#

So:

#M_("eth")=(13.9xxM_("soln"))/(100)#

#M_("soln")="density"xx"volume"=0.611xx50=30.55"g"#

So:

#M_("eth")=(13.9xx30.55)/(100)=4.2"g"#