Question #8b3fa
1 Answer
In the case of
This means that the charges on the two complex ions will be equal. You can thus break up the coordination complex into a cation and an anion
Notice that the anion contains the cyanide anion,
Let
Now look at the cation. Since ammonia is a neutral compound, the overall charge of the cation must be equal to the charge of the metal. This means that you have
Use equations
Therefore, the charge of the metal will be +3 and the two complex ions will be
You can use the same approach for the second coordination complex. This time, however, the two complex ions do have subscripts. This means that you have
So, ethylenediamine is a neutral compound, so the oxidation state of cobalt will match the overall charge of the complex ion. Thus, you're dealing with the
Once again, use a simple equation to find the charge of the manganese ion. This time, in addition to the negative charge that's coming from the cyanide anion, you get an extra -1 charge from the iodide anion,
Therefore, you're dealing with the