# Question #90394

##### 1 Answer

The *volume by volume percent concentration* of your solution will be equal to **0.991%**.

You know that your acetic acid solution has a density equal to that of water, more specifically to

Since molariy is defined as moles of solute, in your case acetic acid, per liters of solution, you can use it to determine how many moles of acetic acid you have.

To make the calculations easier, you can assume a **1.00-L** sample of solution.

Use acetic acid's molar mass to determine how many grams you'd get in your sample

Now you can use the solution's density to see what volume this much acetic acid would occupy

I've converted the volume to liters because it will make the calculation of the v/v percent concentration easier.

So, you know that for *every* **1.00 L** of solution, you get **9.91 mL** of acetic acid. This means that its v/v percent concentration will be

On average, regular vinegar is about 5% v/v, which means that your solution is roughly 5 times more dilute than that.