Question #937d0

1 Answer
Alan P.
May 28, 2015

Assuming a atmospheric pressure of 1:
11 calorie (or "gram-calorie" as opposed to the "dietary-calorie") is the amount of energy required to raise the temperature of 11 gram of water 1 C^@1C∘

To raise the temperature of 1010 grams of water 15 C^@15C∘ (from 10^@ C10∘C to 25^@ C25∘C)
would require
10 xx 15 = 15010×15=150 calories

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