# Question #3aabb

##### 2 Answers

The solution will be **basic**.

Start with the balanced chemical equation for this neutralization reaction

Notice that you have a *complete* neutralization to take place, you need **equal amounts of moles** of the two compounds.

If you have more moles of acid than of base, the solution will have an excess of hydronium ions, *acidic*.

If you have more moles of base, the solution will hve an excess of hydroxide ions, *basic*.

Use the molarities and volumes of the two solutions to determine how many moles of each you have

and

You have more moles of calcium hydroxide present, which means that the sulfuric acid will be **completely consumed** by the reaction and you'll only be left with

Therefore, the solution will be **basic**.

If you need to calculate the pH as well, use the dissociation of calcium hydroxide to get the number of moles of hydroxide ions present

You'll get twice as many moles of hydroxide ions than you have of the *remaining* calcium hydroxide. Use the total volume of the solution to determine the molarity of the

From there, determine pOH and pH.

I don't want the initial answer to become very long, so I'll just show you how to get the solution's pH here.

So, you know that your reaction left you with excess calcium hydroxide, which is a *strong base*. In your case, calcium hydroixde will dissociate completely to produce calcium cations,

Notice that you get **moles** of hydroxide ions for *every mole* of calcium hydroxide that dissociates. SInce you were left with **0.00075 moles** of

To get the molarity of the hydroxide ions, use the *total volume* of the solution

This will get you

**SIDE NOTE** *Don't forget to convert mL to L when calculating molarity!*

Since you know the concentration of the hydroxide ions, you can determine the solution's pOH by

THis means that the solution's pH will be