# Question #c6d6a

##### 2 Answers

#### Answer:

Time of flight

Maximum vertical height

Horizontal range

#### Explanation:

Your projectile is fired with an initial velocity of **22 m/s** and at an angle of

This means that the motion of the projectile has a *vertical* component and a *horizontal* component.

**Vertically**, the projectile will be acted upon by the *gravitational acceleration*,

*total vertical displacement*;

In your case **zero** because the projectile starts from the ground level and ends up on the ground level. The vertical component of

The equation becomes

The only acceptable solution is

At the maximum vertical height, the vertical component of the velocity is **zero**. This means that you can write

Solving this equation for

**Horizontally**, the projectile is not acted upon by any forces. This means that you can write

Use the values you have to solve for

#### Answer:

1) time of flight =2.44sec 2) maximum vertical height= 7.30 metre

3)horizontal range= 82.6

#### Explanation:

it is defined as the time taken by any object to travel in any medium it is calculated by

t=2vsintheta/a

maximum vertical height is the peak of that projectile motion the object is travelling

horizontal range it is the range of horizontal motion which is done by object