Question #e66a1

1 Answer
Jun 14, 2015

Answer:

Under those conditions for temperature and pressure, 0.3 moles of methane would occupy that volume.

Explanation:

You have all the information you need to solve for the number of moles of methane that would occupy 4.3 L at a temperature of 400 K and a pressure of 2 atm.

Your tool of choice will be the ideal gas law equation

#PV = nRT#, where

#P# - pressure;
#V# - the volume the gas occupies;
#n# - the number of moles of gas;
#R# - the ideal gas constant, equal to #0.082("atm" * "L")/("mol" * "L")#
#T# - the temperature of the gas.

Plug your values into the equation and solve for #n#

#PV = nRT => n = (PV)/(RT)#

#n = (2cancel("atm") * 4.3cancel("L"))/(0.082(cancel("atm") * cancel("L"))/("mol" * cancel("K")) * 400cancel("K"))#

#n = "0.262 moles"#

Rounded to one sig fig, the number of sig figs you gave for the temperature of the gas, the answer will be

#n = color(green)("0.3 moles")#