mass of potassium hydroxide (
= (1.23 x 2) (39 + 1 + 16)
Mass of potassium hydroxide needed: 138 g
Start by writing the balanced chemical equation for this neutralization reaction
Notice that you have a
Simply put, for a number of moles of potassium sulfate produced, twice as many moles of potassium hydroxide reacted.
You know that the reaction produced 1.23 g of potassium sulfate, which means that the number of moles of potassium hydroxide that reacted is
To get the mass of potassium hydroxide that would contain this many moles, use the compound's molar mass.
A substance's molar mass tells you what the mass of 1 mole of a substance is.