# Question #3134c

Sep 28, 2015

Point of inflexion is at x=2

#### Explanation:

First find y'= $- x {e}^{-} x + {e}^{-} x$

Next find y" = $x {e}^{-} x - {e}^{-} x - {e}^{-} x$

= $\left(x - 2\right) {e}^{-} x$

Equate the second derivative to 0. It works out x=2

Inflexion point is at x=2