Question

Question #68c84

Answer 1

`sqrtx/2-(2x^10)/5+C`

Explanation:

`int(sqrtx-4x^10)/x dx=intsqrtx/xdx-int(4x^10)/x dx=`

`=intx^(-1/2)dx-4intx^9dx=1/2x^(1/2)-4 x^10/10+C=`

`=sqrtx/2-(2x^10)/5+C`