Question #46b17

1 Answer
Nov 10, 2015

#r(t)=(1/2t^2+3)hati + (e^t-1) hatj #

Explanation:

#r(t)=intv(t)dt=int(t hat i +e^t hat j)dt#

#=(1/2 t^2 +C) hat i + (e^t +D)hatj #.

But since #r(0)= 3 hat i, => C=3 and D=-1 #

Hence #r(t)=(1/2t^2+3)hati + (e^t-1) hatj #