Question #4323e

1 Answer
Apr 1, 2016

Answer:

The β-oxidation of an 18-carbon acid produces #"9 mol of Acetyl-CoA, 8 mol of NADH, and 8 mol of FADH"_2#.

Explanation:

The β-oxidation pathway for a saturated fatty acid is a four-step cycle.

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A #"C"_18# acid (stearic acid) enters as #"stearyl-CoA"#.

Each pass through the cycle removes 2 carbon atoms and generates 1 molecule each of #"acetyl-CoA, NADH, and FADH"_2#.

The first seven passes through the cycle remove 14 carbon atoms and generate 7 molecules each of #"acetyl-CoA, NADH, and FADH"_2#.

In the eighth pass, the remaining 4 carbon atoms are converted to 2 molecules of #"acetyl-CoA"# and 1 each of #"NADH"# and #"FADH"_2#.

This makes a total of #"9 acetyl-CoA, 8 NADH, and 8 FADH"_2#.

The overall equation for the β-oxidation of #"stearyl-CoA"# is:

#"CH"_3("CH"_2)_16"CO-SCoA" + "8FAD" + "8NAD"^+ + "8HSCoA" + "8H"_2"O" → color(red)(9)"CH"_3"CO-SCoA" + color(red)(8)"NADH" + color(red)(8)"FADH"_2 + "8H"^+#