Question #e951f

1 Answer
Jan 14, 2016

Answer:

#10^6# fluorine molecules have a mass of #(10^6cancel("molecules"))/(6.022xx10^23*cancel("molecules")*cancel(mol^-1)) xx 38*g*cancel(mol^-1)# #=# #??g#

Explanation:

Of course fluorine exists as the gaseous #F_2# molecule at normal temperatures and pressures. A million fluorine molecules will not have a very large mass.

I used Avogadro's number in the calculation above, because I know that Avogadro's number (i.e. a MOLE) of fluorine ATOMS (i.e. #6.022xx10^23# fluorine atoms) has a mass of #19.00# #g# precisely. What is the mass of Avogadro's number of fluorine molecules?