Question

Question #ee719

Answer 1

calculation may be done as follows

Explanation:

0.36 M `H_2SO_4` means 0.72 N `H_2SO_4`
25 mL of this solution contains `25*0.72/1000` gmEquivalent acid = 0.018 gm Equivalent acid
So for neutralization same gm Equivalent `NaHCO_3`will be needed
Equivalent mass of `NaHCO_3`
= Formula mass/1
=23+1+12+3x16 =84
hence reqd amount of salt = 0.018x84 g=1.512 g

pl, inform if error exists