# Question #ee719

##### 1 Answer

Feb 19, 2016

calculation may be done as follows

#### Explanation:

0.36 M

25 mL of this solution contains

So for neutralization same gm Equivalent

Equivalent mass of

= Formula mass/1

=23+1+12+3x16 =84

hence reqd amount of salt = 0.018x84 g=1.512 g

**pl, inform if error exists**