# Question 423de

Mar 2, 2016

58°C

#### Explanation:

We are given the following

$P$ = 7.25 atm
$V$ = 1.52 L
$n$ (mol) = .406
$R$ = .0821 $\frac{L \cdot a t m}{m o l \cdot K}$
$T$ = unknown
we are asked to find temperature. Using the ideal gas law $P V = n R T$, we can plug in what we are given

$\left(7.25 a t m\right) \left(1.52 L\right)$ = $\left(.406 m o l\right) \left[\frac{.0821 L \cdot a t m}{m o l \cdot K}\right]$(T)

rearrange everything to solve for $T$;

$T$ = ((7.25atm)(1.52L))/([(.0821 L *atm)/(mol *K)] (.406mol) 

$T$ = 331°K; to get to °C, -273$K$

$T$ = 58°C#