# Question #54a62

$K r : 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10} 4 {p}^{6}$ and $X e : 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10} 4 {p}^{6} 5 {s}^{2} 4 {d}^{10} 5 {p}^{6}$
But if you want it to be hassle free and simplified, you can just write down the previous noble gas and add the remaining configuration. In this case, $K r : \left[A r\right] 4 {s}^{2} 3 {d}^{10} 4 {p}^{6}$ and $X e : \left[K r\right] 5 {s}^{2} 4 {d}^{10} 5 {p}^{6}$.