Question #973fb

1 Answer
Feb 13, 2016

Answer:

#8.98# #xx# #N_A#, where #N_A# is Avogadro's number, #6.022xx10^23# #mol^-1#.

Explanation:

So the answer is # ~= # #54xx10^23# individual formula units of #AlCr_2O_7Cl#. In this quantity, how many individual ATOMS of aluminum, of chromium, of oxygen?