Question #973fb

1 Answer
anor277
Feb 13, 2016

#8.98# #xx# #N_A#, where #N_A# is Avogadro's number, #6.022xx10^23# #mol^-1#.

Explanation:

So the answer is # ~= # #54xx10^23# individual formula units of #AlCr_2O_7Cl#. In this quantity, how many individual ATOMS of aluminum, of chromium, of oxygen?

Related questions
See all questions in The Mole
Impact of this question
1494 views around the world
You can reuse this answer
Creative Commons License