First we acknowledge that
Consulting the data with which we have been provided, the most obvious progression would be to calculate the moles of
N.B. you would be wise to keep this number in your head in future, given the prominence of water in this discipline.
In this question we must simply find the number of moles of hydrogen gas we required to make this much water, so we need only consult the reaction's mole ratio. Let's look at the formula, which I have decided to construct for the preparation of one mole of water from hydrogen and oxygen gases:
Notice that we could have doubled up these coefficients for a slightly friendlier-looking equation, but expressing the reaction in this way makes our mole ratio much more obvious and, if you're given marks in an exam for showing working, you don't need to employ a useless
Start with a balanced equation.
Determine molar mass of
Determine the moles of water that was produced by dividing the mass of water produced by its molar mass.
I am leaving a few extra digits to reduce rounding errors. The final answer will be rounded to two significant figures.
Next determine the moles of
This problem can be worked out all at once by combining the steps.