Question #15837

1 Answer
Feb 10, 2016

Answer:

The uncertainty in the sum #"(0.032 ± 0.001 g) + (0.033 ± 0.001 g)"# is #"±0.002 g"#.The average of the two measurements is # "0.032 g"#, with an uncertainty of #" ± 0.001) g"#

Explanation:

The units don't matter, so let's deal with just the numbers.

#"0.032 ± 0.001"#
#"0.033 ± 0.001"#
#stackrel(——————)("0.065 ± 0.002")#

The sum of the two numbers is #0.065#, with an uncertainty of #± 0.002#.

The average of the two numbers is

#"0.065 ± 0.002"/2 = 0.032 ± 0.001#

Your uncertainty is in the third decimal place, so you can have no more than three decimal places.

You must round off your calculator's answer of #0.0325# to #0.032#.