Question

You have `28*g` dinitrogen, and `24*g` of dihydrogen. What is the limiting reagent with respect to ammonia formation?

Answer 1

Dihydrogen is in excess, so dinitrogen is the limiting reagent. Approx. 34 g of ammonia can be produced.

Explanation:

`N_2(g) + 3H_2(g) rarr 2NH_3(g)`

You have approx `1` mol `N_2` and `12` mol `H_2`. If you assume 100% yield, 2 mol ammonia should result. Of course, the actual production of ammonia gets nowhere near these yields.