Question

Question #9f671

Answer 1

Let compute `g` hence

#g(x)=lim_(h->0)((x+h)^2 -x^2)/h= lim_(h->0) [x^2+2xh+h^2-x^2]/h= lim_(h->0) [h(2x+h)]/h=2x#

Finally `g(x)=2x`

We want `g(x)=2` hence

`g(x)=2=>2x=2=>x=1`