Question #aa189

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Answer 1 · 2017-04-12T13:35:36

#k=0.#

#p(x)=x^2-x-2.#

To find #k#, such that, #AA x,p(x+k)=p(x-k).#

Now, #p(x+k)=p(x-k),#

#rArr (x+k)^2-(x+k)-2=(x-k)^2-(x-k)-2,#

#rArr x^2+2kx+k^2-x-k-2=x^2-2kx+k^2-x+k-2,#

#rArr 4kx-2k=0, or, 2k(2x-1)=0#

#rArr k=0.#