Question #8138e

1 Answer
Feb 28, 2016

Answer:

#a=7" ; "b=1#

Explanation:

Given: #h(x)-> x^2+1" "k(x)-> ax+b#

'~~~~~~~~~~~~~~~~~~~~~~~
Condition 1

#h(0) =k(0) -> (0)^2+1 = a(0)+b#

#=> b=+1#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Condition 2

Now we have: #h(x)-> x^2+1" "k(x)-> ax+1#

#k(2)-> 15=ax+1#

#ax=14#

#a(2)=14#

#a=7#