Question #b3989 Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Binayaka C. Mar 1, 2016 # n=4 or n= -1# Explanation: #6n^2-18n-18-6=0 or 6n^2-18n-24=0 or n^2-3n-4=0 or n^2-4n+n-4=0 or n(n-4)+1(n-4)=0 or (n-4)(n+1)=0 :. n=4 or n= -1# [Answer] Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1179 views around the world You can reuse this answer Creative Commons License