How do you solve #-4x^2+4000x=0#?

1 Answer
Mar 2, 2018

Answer:

The solutions are #x=0,1000#.

Explanation:

Simplify the quadratic by dividing by #-4#, then factor out an #x# term. Lastly, solve for #x# in the expression that equals #0#.

#-4x^2+4000x=0#

#(-4x^2+4000x)/color(red)(-4)=0/color(red)(-4)#

#x^2-1000x=0#

#x(x-1000)=0#

#x=0,1000#

The solutions are #x=0# and #x=1000#. You can verify this answer by seeing where the parabola #y=-4x^2+4000x=0# crosses the #x#-axis. (It crosses at #0# and #1000#.)

graph{-4x^2+4000x [-1000, 2000, -1000000, 1500000]}