# Question #1068c

##### 1 Answer

Jun 5, 2016

#### Answer:

#### Explanation:

Let

#m->"Mass of satellite" # #M->"Mass of Earth" # #R->"Radius of Earth" =6400km# #h->"Height of the orbit from surface of the Earth" =900km # #v->"Orbiting speed of the satellite" # #G->"Gravitational constant" # #g->"Acceleration due to gravity" =9.8xx10^-3kms^-2#

Now we know

Now inserting the values in equation (1) we get