# Question 38980

Mar 13, 2016

${\text{CoSO"_4+"Pb(NO"_3)_2->"Co(NO"_3)_2+"PbSO}}_{4}$

#### Explanation:

Reactants:
1. Cobalt (II) $\implies$ An ion of Cobalt, Co
having valency of $2 + \implies {\text{Co}}^{2 +}$ and Sulfate $\implies {\text{SO}}_{4}^{2 -}$ ion
Combining both the chemical formula of first reactant is ${\text{CoSO}}_{4}$
2. Similarly Lead (II) $\implies {\text{Pb}}^{2 +}$
and Nitrate $\implies {\text{NO}}_{3}^{-}$ ion
Observe that each ion of Lead will require two ions of nitrate to satisfy (quench) its valency. Therefore, combining both we obtain chemical formula of second reactant as "Pb(NO"_3)_2

Products:
Following the same logic as used for reactants
1. Cobalt (II) Nitrate has chemical formula as "Co(NO"_3)_2#
and
2. Lead (II) Sulfate has chemical formula as ${\text{PbSO}}_{4}$

Writing the chemical equation of the reaction
Reactants $\to$ Products

${\text{CoSO"_4+"Pb(NO"_3)_2->"Co(NO"_3)_2+"PbSO}}_{4}$
Inspection reveals that the equation is already balanced.