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Question #954f6

1 Answer

Mar 8, 2016

$sin theta = (-3sqrt10)/10$

Explanation:

$cot theta$ = adjacent /opposite
$h^2=o^2+a^2=1^2+(-3)^2$
$h=sqrt10$
$sin theta$ =opposite/hypotenuse
$sin theta = (-3sqrt10)/10$

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