Question #b5376

1 Answer
Mar 15, 2016

Answer:

#8.3997 #x# 10^25# atoms of #Cu#

Explanation:

  1. We need to balance the equation to determine the mole ratio of #Cu# against the #Cu_3FeS_3#;
  2. The balanced equation is:
    #2Cu_3FeS_3 + 7O_2 -> 6Cu = 2FeO + 6SO_2#
  3. Find the formula mass of bornite, by locating the atomic masses of the elements composing the copper ore, which is equal to 344 grams per mole;
  4. To start the calculation, you are provided with the mass of the raw material of #20 kg# which has 80% purity. Meaning #80%# of the raw material is bornite (copper ore). To find the mass of copper ore, multiply the mass by its purity; so that
    #20 kg #x# 0.80=16 kg# of pure bornite
  5. Convert the mass (kg) of pure bornite to grams to be consistent with the units being used in the formula mass; (#16,000# grams)
  6. Again, #16,000# grams bornite will be converted to mole bornite by multiplying with the mole ratio reflected on the balanced equation above to arrive #139.53# mole #Cu#;
  7. Since #1 mol Cu=6.02 #x# 10^23# atoms #Cu#, multiply the answer in step 6 by the conversion factor taken from this equaivalent statement, which is #(6.02 x 10^23 atms Cu)/(1 mol Cu)#;
  8. The answer is computed as 8.3997 x #10^25# atoms #Cu#