# Question #b5376

##### 1 Answer

Mar 15, 2016

#### Answer:

#### Explanation:

- We need to balance the equation to determine the mole ratio of
#Cu# against the#Cu_3FeS_3# ; - The balanced equation is:

#2Cu_3FeS_3 + 7O_2 -> 6Cu = 2FeO + 6SO_2# - Find the formula mass of bornite, by locating the atomic masses of the elements composing the copper ore, which is equal to 344 grams per mole;
- To start the calculation, you are provided with the mass of the raw material of
#20 kg# which has 80% purity. Meaning#80%# of the raw material is bornite (copper ore). To find the mass of copper ore, multiply the mass by its purity; so that

#20 kg # x# 0.80=16 kg# of pure bornite - Convert the mass (kg) of pure bornite to grams to be consistent with the units being used in the formula mass; (
#16,000# grams) - Again,
#16,000# grams bornite will be converted to mole bornite by multiplying with the mole ratio reflected on the balanced equation above to arrive#139.53# mole#Cu# ; - Since
#1 mol Cu=6.02 # x# 10^23# atoms#Cu# , multiply the answer in step 6 by the conversion factor taken from this equaivalent statement, which is#(6.02 x 10^23 atms Cu)/(1 mol Cu)# ; - The answer is computed as 8.3997 x
#10^25# atoms#Cu#